[SOLVED] system verilog squareroot with out rounding....

dipin · Nov 25, 2014

hi,

in system verilog , to find the square root $sqrt(x) function can be used . but it is rounding the values.

example if the input value is 95 then $sqrt(x) will give root as 10.
is there any way to get it as 9??????

i have tried t**0.5 also. but it too rounding the value.:???:

i am new in system verilog. if you know please help.

thanks & regards

FvM · Nov 25, 2014

$sqrt() doesn't perform any rounding, it takes place because you assign the result to integer variable.

To get the intended result, learn about $floor() and $ceil(). You should also get a basic understanding of numeric types and automatic type conversions in SV to solve similar problems yourself.

dipin · Nov 25, 2014

hi,

thanks fvm . i used $floor()

regards

[SOLVED] system verilog squareroot with out rounding....

dipin

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dipin

dipin

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[SOLVED] system verilog squareroot with out rounding....

dipin

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