check this
**broken link removed**
Basically, you operate the motor at reduced current with reduced torque. In any case, the current sense resistors and Vref most be dimensioned for the intended output current. It's constant current PWM mode.
P.S.: I just realized, that the above linked L298 H-bridge circuit simply shorts the sense terminals to ground. In other words, it's operating the stepper motor in constant voltage rathe than constant current mode. This can only work with a stepper motor with sufficient phase winding resistance. No fast stepper motor will have it.
It's not clear to me, if you actually need 4A? If so, you would need one L297 and two L298, or any other circuit that can generate phase signals with PWM current control in place of the L297.and to get the 4A the datasheet refers too should i do the combination of PIC-l297-L298N for each winding?
technical data NEMA23 motor
max voltage [VDC] 60
nominal voltage [VDC] 24-48
nominal current [A] 4,2
holding torque [Nm] 2,0
In the first post you said that you have a 20v/4A source (which will probably not be enough for two phase drive but you can use one phase) and if I understand the data you have provided correctly you have a motor that works well within the current range with 20v supply (nominal voltage [VDC] 24-48).
If this is the case then you don't need to use the PWM because the current will be limited anyway from the coil resistance so you can just use a discrete circuit like A simple H-Bridge design « PocketMagic and just provide the correct steps.
For bipolar operation modes check Stepperworld Bipolar Tutorial
Can you verify that the resistance of your motor is more than 5-6 ohms?
Alex
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