Hi All,
When I plug in 24DC positive wire to one AC in and then plug in the other negative wire to other AC in. there is a very minute spark for a very very brief moment. Then the circuit works fine.
I am not sure what you are doing.........are you bypassing the rectifier?
The two ac lines goes into the rectifier and then. Smoothing capacitor of 220uf smooths out the positive ac with very little ripple. It then passes through the volt reg that gives out 10 volt DC. Then led is and resistor takes in 40ma current.
When DC is plugged it also goes through rectifier. Same process but its a DC so smoothing cap has no use. The DC volt goes thru regulator then to led and res
Ac works fine but for DC when I connect the wires there is an initial brief spark... Why is this happening?
Sounds like inrush. The 220uF capacitor starts off with no charge, and so briefly resembles a short as it quickly charges from 0V to 24V, drawing a spark.
I think he omits the 220uF cap in the DC 'version'.
then i added one more 0.47uF cap in parallel to the 220 cap to see if that filter cap does something but nthg happened... still there is spark when i use 24 DC.
at one point my voltage regulator went bad... could it be because of that constant touching and removal of wire?
The wires will be conneced to a switch. It can be a manual switch or a IC controlled switch... If its a IC controlled switch I am worried this might cause the IC to go bad.
Yes. Why do you feel the need to keep 'playing' around!
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Not if the IC was properly wired in - you need to give specifics on which IC and how it will be connected.
at one point my voltage regulator went bad... could it be because of that constant touching and removal of wire?
Well maybe, if you have a lot of stray inductance, inrush current sufficient to cause a spark also caused a higher peak voltage. 24V is already close to the max voltage of most common linear regulators.
But that's just speculation. Run down other possibilities too. At 24V in, 10V out, and 40mA, your regulator is dissipating (24-10)*0.04=560mW of heat. Is the package/heatsinking sufficient for that?
It wil be an IC switch controlled by a high and low signal...
I
and no matter how much i play around the design should not blow up anything.
If it s blowing up reguklator means there is a bproblem.
I need to find out because the led light is supposed to blink... continuosly for 1 minute which is turning off and on continuously
The voltage regulator is rated for 400mA of current. I am only using 40mA.
Also yes i even have a heat sink attached to the voltage regulator... there is no heat dissipation on the PCB circuit.
I can't tell if you're already aware of this from your wording, but it's important enough to state anyway. Regulators have separate limits for both current and power (heat) dissipation. You cannot exceed either. Linear regulators "burn off" excess voltage as heat, and the larger the voltage drop they must produce, the less current they can produce before they reach the dissipation limit. If you post the part and package you're using, I can verify it's being used within limits for you.
As for the spark:
1) If it is caused by inrush, there really should be no problem, and it should also be able to handle any number of power cycles. Linear regulators are made to handle sudden application of power with no special precautions. The previous failure may have simply been a fluke, or slip of a test lead. If there is also an unusually high inductance somewhere causing a voltage spike exceeding the regulator's max voltage, it can be damped by adding a 4.7 ohm 1/4W resistor before the input capacitor to limit the peak current.
2) If it is not caused by inrush, it could be a faulty part, wiring error, or almost anything - which unfortunately we have little chance of discovering.
The spark is due to the sudden charging current of filtering capacitor in starting...You have to combine a small 10 to 50 ohm resistor in series with filter capacitor...
and Also it will protect the Diode from damaging due higher surge current.....
As for the spark:
1) If it is caused by inrush, there really should be no problem, and it should also be able to handle any number of power cycles. Linear regulators are made to handle sudden application of power with no special precautions. The previous failure may have simply been a fluke, or slip of a test lead. If there is also an unusually high inductance somewhere causing a voltage spike exceeding the regulator's max voltage, it can be damped by adding a 4.7 ohm 1/4W resistor before the input capacitor to limit the peak current.
The spark is due to the sudden charging current of filtering capacitor in starting...You have to combine a small 10 to 50 ohm resistor in series with filter capacitor...
and Also it will protect the Diode from damaging due higher surge current.....
Thanks Guys, that was it. Without the resistance the capacitor was trying to get charged instantly so it was taking up huge inrush current. Once the resistor or was put in then the current was limited so it didnt have the huge inrush, thus its working now with no spark.
Thanks everyone who helped out. Seems like any resistance value will work here.
Is there any requirement or formula i need to use to calculate the resistance value needed? that changes with the value of the capcitor?
I am using the 220uF cap so what value will be good?
Thanks again
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