Solution to 8n^2>=64nlgn equation

[BAT_MAN]

Can anyone solve this equation

8n^2>=64nlgn

 

[zefreh]

how to solve n>8logn

Can anyone solve this equation

8n^2>=64nlgn

by supposing that log is in base 2 we have :

8n^2>=64nlgn => n>=8logn => 2^n>=n^8 => n=1 (if n is a natural number)

 

[bunalmis]

64nlgn = n

8n^2>=64nlog

n=8log
n/8=log

10^( n / 8 )=n

with calculator n~=6.5

 

[zajbanlik]

8n^2<64nlgn怎么求

If n is integer than is solution n=1 or n>=7.

 

[fal_con]

Re: Solve equation

I solve the equation through numerical computation and get n=43 solution at this both equation are equal.