Continue to Site

Welcome to EDAboard.com

Welcome to our site! EDAboard.com is an international Electronics Discussion Forum focused on EDA software, circuits, schematics, books, theory, papers, asic, pld, 8051, DSP, Network, RF, Analog Design, PCB, Service Manuals... and a whole lot more! To participate you need to register. Registration is free. Click here to register now.

Sine wave segment area computation

Status
Not open for further replies.

jeep brainy

Newbie level 4
Newbie level 4
Joined
Oct 30, 2009
Messages
6
Helped
0
Reputation
0
Reaction score
0
Trophy points
1,281
Location
ireland
Activity points
1,314
Hi Everyone,
I need to derive a formula for computing an area of a segment within a sine wave.

Given the length of chord (X) and wavelength (Z), how would I get the area of segment A. Many thanks in advance for any help.

Presentation1-2.png


Cheers,
Jeep

---------- Post added at 06:55 ---------- Previous post was at 06:52 ----------
 
Last edited:

The problem is about calculating a definite integral ∫sin x - a dx. As a hint: ∫sinx dx = -cos x
 

Hi FvM,
Thanks for your reply but could you further explain.
Please note on those to variables (x and z), I want to compute for the area using them.

cheers,
jeep
 

The limit angle is: θo = acos(x/(2z))

Then the whole grey area:
A = 4 ∫(cos(x) - cos(θo))dx ; 0,θo

A = 4 (sin(x) - x cos(θo)) |0,θo = 4 ( sin(θo) - θo cos(θo))

A = 4 ( √(1-(x/(2z))²) - (x/(2z)) acos(x/(2z)))
 

Status
Not open for further replies.

Part and Inventory Search

Welcome to EDABoard.com

Sponsor

Back
Top