Eshal
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Hello sir, here are these designs:Yes, of course.
...I circled a point with blue in color. Does my capacitor value lay there sir?
...we have never been taught how to read graphs in datasheets...
Yes, sir I know this but I thought in parallel path current is divided so heat dissipation will be low but in series current remains same so heat dissipation too. Isn't it? That's why I chose shunt. By the way, I like your name. A schmitt trigger. heheheheheheh.... nice name sir.Why do you want a shunt? A shunt regulator wastes more heat than a series regulator across its operating range.
Whereas on a series regulator the waste heat approaches zero at minimal load and increases fairly linearly with increasing load, on a shunt regulator it wastes maximum power at all loads.
I know, my regulator performance is poor. But I still want to design it. I don't want to jump high. I want to be basic through my learning of designing power supply. The simplest power supply. As I succeed in this then I will improve my power supply.Your regulator using the darlington has poor voltage regulation because it is missing an error amplifier.
The base-emitter voltage drop of the darlington increases when the load current increases so that is when the output voltage will noticeably drop.
The circuit with two separated transistors has some voltage gain but not enough to make a good regulator.
The shunt regulator will work as poorly as the zener diode in it except the transistor boosts the current.
...I thought in parallel path current is divided so heat dissipation will be low but in series current remains same so heat dissipation too. Isn't it?...
This is a very good idea.I don't want to jump high. I want to be basic through my learning of designing power supply. The simplest power supply. As I succeed in this then I will improve my power supply.
Before you calculate any values, you need to understand how the circuit works. Did you figure that out yet?How to start calculating values of R1 and R2?
Yes, Here it is with schematic below:Before you calculate any values, you need to understand how the circuit works. Did you figure that out yet?
Can you write a simple explanation of how it works? No fancy formulas, just a simple description.
Yes sir, I will do it for sure. But after designing this one. After this, I will try to improve my design. Just say, I am a dumb student in electronics you are trying to teach.It's probably a good idea to replace Q1 with a Darlington such as TIP121 or BD677.
For a 5V output then the zener must be 4V or less ijn your circuit. But a document about zener diodes shows that a 6.5V zener is good, a 6V zener is fair, a 5V zener is not good, a 3.3V zener is bad and a 2.2V zener is horrible. the graph shows the amount the voltage changes when the zener current changes. A good zener shows a vertical line and a resistor that has no voltage regulation shows a slanted line like the poor zener diodes.By the way, why low voltage zener?
You listed some important spec's but the current gain is also important. A TIP31 power transistor has a minimum current gain of only 22 at a collector current of 1.5A then its base current is very high at 68mA.how to choose my desired transistor? Are there any specific parameters which should be considered in choosing transistor like diode in which we consider reverse voltage, forward voltage, forward current and its power. So is there any specification with transistor too?
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