You need to define the output too. Because in the configuration you mentioned, if you take voltage output, voltage source wouldn't interact with the filter at all.
But in general to be able to understand it intuitively I usually think of parallel LC as a resistor that is short for every frequency except the tuning frequency, and series LC as a resistor that is open for every frequency except the tuning frequency.
So if you drive with a current source and take "voltage across LC" as output, you'd see a peak at tuning frequency, but since you have that resistor over there that peak is not as sharp as or not as infinite as (stupid I know) it would be had there been no resistors anywhere. Even if you don't put that resistor, the limited Q values of LC shows up as resistor, reducing your Q (recursive answer because that's the definition of Q).
To explain other scenarios you have to define them.