If "disconnecting" is easily achievable, it's the preferred method. Mostly it's not feasible.
As told, by measuring supply net voltage drop.Which Methods would you do?
you said one component was doing that, and you desoldered them one by one to find it)?
Yes, there are many components connected to +5V or +3V. There are not many components connected to +5V and +3V.Yes there is multiple collector resistors , pull resistors, IC chip pins , Transistors pins, FETS pins, some go to the Vcc +5 volts or others go to Vcc +3 volts
I would use the method that I sketched in post #36. It can work for shorts between nets as well.Yes how else would u do it? to track down the SHORT or shorted component?
I'm using a lab power supply, set to a low out voltage, e.g. 0.1 V and current limit 100 mA - 1 A, depending on the involved trace width. Than inject the current between the shorted nets and trace the voltage drop along the circuit.
I'm using a lab power supply, set to a low out voltage, e.g. 0.1 V and current limit 100 mA - 1 A, depending on the involved trace width. Than inject the current between the shorted nets and trace the voltage drop along the circuit.
Than inject the current between the shorted nets and trace the voltage drop along the circuit.
The short itself may have a voltage drop, but usually it hasn't. The voltage drop occurs along the traces between the short and the point where you connect the power supply. So it indicates the location of the short.I thought a Short doesn't have a voltage drop right?
A low voltage of 0.1V doesn't forward bias semiconductors. There may be other components that can be damaged with 1A, in this case you should reduce the current limit setting.Can you inject 1 amp of current? won't that damage the transistors,fets and IC chips?
A low voltage of 0.1V doesn't forward bias semiconductors. There may be other components that can be damaged with 1A, in this case you should reduce the current limit setting.
The current should be large enough to see voltage drops.
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