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I disagree.
Zin to coax is not affected by left side or impedance of the source. Thus matching source is not required for my statement to be true.

The Zout will also be 10k + 50 Ohms but with a delayed attenuated source Vs and the return loss at both source and load will be low (meaning high reflections.

To match all impedances and attenuate may be desirable.
The proper method is to delete the source 10k to match the source and make an output pad with desired Av=attenuation, Zin = 50 and Zout as desired to match the filter unless otherwise specified as low Ohm source.

If using a series LC BPF. you want a low Rs for high Q and tap out between LC for BW. e.g. 50.1: 0.1 attenuator
If using a Parallel LC BPF, you want a current source CE amp with some load or series hi-R for desired Q
If it is a ceramic resonator , follow specs.

<blockquote data-quote="D.A.(Tony)Stewart" data-source="post: 1784411" data-attributes="member: 134022">I disagree.Zin to coax is not affected by left side or impedance of the source. Thus matching source is not required for my statement to be true.The Zout will also be 10k + 50 Ohms but with a delayed attenuated source Vs and the return loss at both source and load will be low (meaning high reflections.To match all impedances and attenuate may be desirable.The proper method is to delete the source 10k to match the source and make an output pad with desired Av=attenuation, Zin = 50 and Zout as desired to match the filter unless otherwise specified as low Ohm source.If using a series LC BPF. you want a low Rs for high Q and tap out between LC for BW. e.g. 50.1: 0.1 attenuatorIf using a Parallel LC BPF, you want a current source CE amp with some load or series hi-R for desired QIf it is a ceramic resonator , follow specs.</blockquote>

[QUOTE="D.A.(Tony)Stewart, post: 1784411, member: 134022"] I disagree. Zin to coax is not affected by left side or impedance of the source. Thus matching source is not required for my statement to be true. The Zout will also be 10k + 50 Ohms but with a delayed attenuated source Vs and the return loss at both source and load will be low (meaning high reflections. To match all impedances and attenuate may be desirable. The proper method is to delete the source 10k to match the source and make an output pad with desired Av=attenuation, Zin = 50 and Zout as desired to match the filter unless otherwise specified as low Ohm source. If using a series LC BPF. you want a low Rs for high Q and tap out between LC for BW. e.g. 50.1: 0.1 attenuator If using a Parallel LC BPF, you want a current source CE amp with some load or series hi-R for desired Q If it is a ceramic resonator , follow specs. [/QUOTE]

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