Resistor network fork DC level shifter

You want Vout=1.25 V with Vin=0, simple calculation for R2.

A comment on your sentence re resistor divider:

The input signal amplitude is not just divided between R1 & R3 as in your calculations. It is instead divides btwn R1 & R2//R3 (R2 in parallel w/ R3). This is because both GND and the 2.5V DC reference from opamp are not moving, so from the point of view of small signal calculations they are both AC grounds (or AC 0V).

=> the signal is attenuated ~1/8th:
+-10V --> +-1.25V (around a 1.25V bias point)

stanislavc said:

+-10V --> +-1.25V (around a 1.25V bias point)

Click to expand...

Isn't it then:
+-10V --> 0...+2.5V

Klaus

Thank you friends, you answered my question and it is clear to me now

KlausST said:

Isn't it then:
+-10V --> 0...+2.5V

Klaus

Click to expand...

Yes, I mistyped. Thank you for correcting.

Dear friends, I have a question.

1. If I want to the shifting without scaling, it means in the circuit from post #1 I have to remove R1 & R3, what will be the consideration for the value of R2? I think I should choose it high so it will neglect the effect of the source impedance.

2. What is the consideration for the opamp used in the circuit with regard to dynamic performance? should it be carefully considered with regard to the signal dynamic properties or only DC performance is enough

Thank you

Junus2012 said:

1. If I want to the shifting without scaling,

Click to expand...

If you want no scaling, they you also have no shifting with the shown circuit.
You need to add an external op amp if you want shifting without scaling.

Junus2012 said:

2. What is the consideration for the opamp used in the circuit with regard to dynamic performance? should it be carefully considered with regard to the signal dynamic properties or only DC performance is enough

Click to expand...

Entirely depends upon the ADC sampling rate and the signal characteristics.
How fast is the signal level changing, and how soon do you need to know what the change is?

Simple passive network :




Regards, Dana.

Hi

for an active "amplification" plus "DC shift" circuit it´s easy to use the standard "differential amplifier ciruit".



Use 2 x 2 resistor values:
R1 = R2
R3 = R4

Where Gain = R3/R1
V1 = inverting source
V2 = noninverting source
VRef = output reference

-----
Some examples:
you want to amplify a -0.5V ..+0.5V signal to a 0... +3.0V signal (ADC_VRef = 3V). Non inverting.
-->
* so the total input span is 1V
* the total output span is 3V
--> you need again of 3
* input center is 0V
* output center is 1.5V (DClevel shift)
-->
Let R1 = R2 be 10k
then because of gain R3 = R4 = 3 x 10k = 30k
for the level shift connect Vref to 1.5V

but maybe you don´t have 1.5V by hand, but the 3V ADC_VRef.
So you may replace "R3= 30k connected to 1.5V" by an equivalent circuit:
To get 1.5V from 3.0V you may use a resistive voltage divider: 1:1:
So R3a = R3b, R3a connected to 3.0V, R3b conected to GND.
Now to get the equivalent to 30k: R3a = R3b = 60k (because R3a and R3b act as if they where connected in parallel)

Klaus