req: C programming help

[isuranja]

I want get following result using nested loop in C.

*
**
***
****
*****
******
*******
********
*********
**********

This is my code but it's not working please do advice.

#include <stdio.h>
main()
{
int i;
int j;

i = 1;
j = 1;

while( i <= 10) {
printf("*");
i = i + 1;
while( j <= 10) {
printf("*/n");
j = j + 1;
}
}
}

Please help on this.

Thanks,
Isuranja

 

[C-Man]

Maybe this can help you??

#include <stdio.h>

void main(void) 
{ 
	int i; 
	int j=1; 

	while(j <= 10) 
	{ 
		i=1;
		
		while(i <= j)
		{
			printf("*");
			i++;
		}
		
		printf("\n"); 
		j++;
	}
}

 

[raj_rohit10]

hi,
I am pointing you the basic problem with code and if u still want any help please write me...
#include <stdio.h>
main()
{
int i;
int j;

i = 1;
j = 1;

while( i <= 10) {
printf("*");
i = i + 1;
while( j <= 10) {
printf("*/n");#here you are using "/n"inspite of "\n" and u have given additional * too so i feel there is no need of loop for "\n" too...As after * printing u required only one \n...so better u print whatever * u wanna in loop and after that u try to go for only one \n.
j = j + 1;
}
}
}

 

[amraldo]

here is more compact code
""
#include<stdio.h>
main()
{
int i, j;
for(i=1; i<11 ; i++)
{
for(j=0;j<i;j++)printf("*");
printf("\n");
}
}

""

 

[aabs]

#include <stdio.h>
void main(void)
{
int a;
int b=1;
while(b <= 10)
{
a=1;
while(a <= b)
{
printf("*");
a++;
}
printf("\n");
b++;
}
}

 

[shafee001]

hi this is your code after adjusment

#include <stdio.h>
#include <conio.H>
main()
{
int i;
int j;

i = 1;
j = 1;
printf("*\n\r");

while( i <= 10)
	{
	j=1;
	printf("*");
	i = i + 1;
	while( j < i)
		{
		if(j==(i-1)) printf("*\n\r");
		else printf("*");
		j = j + 1;
		}
	}
getch();
}