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You get increased voltage .. and it may drive a lot of current...can this cause any damage at 2nd circuit
I want to replace output of a ampifier(lm386) which is a speaker with an aux cable, so I can use amp circuit to have more sensitive sound recorder.
Hi,
You can use it to
* increase gain
But it also has some drawbacks:
* increased noise
* increased distortion
You get increased voltage .. and it may drive a lot of current...
So there is a possibility that your "2nd circuit" (whatever this is) may not withstand this.
btw: the output capacitor is calculated for the speaker impedance. Thus the cutoff frequency may become very low.
Klaus
Surely you can; but the aux output follows some standard for compatibility. Aux output is designed to be fed into a power amplifier.
In this particular case, the speaker is a low power one and connecting the aux output to the speaker may work but you cannot connect that directly into ANY aux input without checking the voltage levels.
Aux signals are what is called at line level; they are usually output from the preamplifier after equalisation, mixer etc and are designed to be fed directly into a power amplifier.
Then the audio amplifier circuit does not work.I found that theres no output sound except the hush and the beep pulse of the led
Then the audio amplifier circuit does not work.
The extremely high value (250uF) of the output coupling capacitor is calculated to charge quickly when feeding an 8 ohm speaker but will take all day to charge into the 100k input of a power amplifier. Did you re-calculate the value of the output coupling capacitor so that it is suitable to feed whatever is the input resistance of your power amplifier?
Your schematic shows a grounded volume control at the input of the LM386 amplifier which is correct only if the input signal is also grounded with no DC voltage on it. Measure if there is any DC voltage on your signal source and block it with a properly calculated coupling capacitor if there is any DC. If the mic is an electret type then it has DC on it and you must block its DC with a coupling capacitor. Use 0.33uF for voices or use 1uF for music.
You did not show the schematic of your blinker so we do not know if it is overloading your voltage regulator. You do not even say what is the voltage that is feeding the voltage regulator. A worn out 9V battery that drops to 6V will not work. Does the input to the regulator have a capacitor to ground as shown on its datasheet?