sakthivel.eee
Junior Member level 3
Dear All,
I have few doubts regarding heat sink calcution. Please help me
Heat sink Thermal resistance is given by
Rsa=((Tj-Ta)/Q)-(Rjc+Rcs)
1. How to find Q for specific ambient temperature? I hope we should not use maximum power dissipation. (Datasheets has curve only case temperature Vs Power dissipation)
Rcs= p*t/a
p= resistivity of interface material
2.Interface material means insulating between heat sink and board or heat sink material's resistivity?
3.How to decide the size of heat sink?
4.For SMD packages, We will give pad in opposite side of the PCB. How to decide the size of that pad?
5. Does anyother parameter should be considered for selecting heat sink?
Thanks in Advance,
Thanks & Regards,
Sakthivel.S
I have few doubts regarding heat sink calcution. Please help me
Heat sink Thermal resistance is given by
Rsa=((Tj-Ta)/Q)-(Rjc+Rcs)
1. How to find Q for specific ambient temperature? I hope we should not use maximum power dissipation. (Datasheets has curve only case temperature Vs Power dissipation)
Rcs= p*t/a
p= resistivity of interface material
2.Interface material means insulating between heat sink and board or heat sink material's resistivity?
3.How to decide the size of heat sink?
4.For SMD packages, We will give pad in opposite side of the PCB. How to decide the size of that pad?
5. Does anyother parameter should be considered for selecting heat sink?
Thanks in Advance,
Thanks & Regards,
Sakthivel.S