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I can't simulate the circuit at the moment but to be honest I'm not sure what C10 does at all.  The LT1716 both drives and sinks current at its output pin so just linking two outputs together would be considered poor practice. It is rated for indefinite shorts but consider what happens if the outputs of U1 and U2 are at opposite levels, you basically short the supply through the output stages. The charge on C10 also has to dump current back into the IC if either output goes to low level. If it is intended to create a delay, the capacitors at the input should be sufficient to take care of that.

Don't worry about Zener current, they will work down to microamp currents. The voltage does vary a little with the amount of current but you don't need to worry about that here. The variation can be calculated by imagining the impedance is a series resistor then using Ohms law to add the voltage across it to the actual Zener voltage.

Brian.