I mean for example in lc oscillator we have lc parallel that they produce sin wave but here there is not something like that to produce sin wave .
I hope I could write my question clearly 8-O8-O8-O
Thanks for response
So if I do not use feedback line I mean just tree caps and tree res that each make 60 phase shift
and a initial condition for first cap on the output I have a sin wave ? or it is only for feedback effect that sin wave is generated ?
If you want an oscillator then you need feedback........................... or it is only for feedback effect that sin wave is generated ?
My main question is thisIf you want an oscillator then you need feedback.
A parallel LC circuit resonates. Its resonance causes it to be a high impedance at the resonant frequency. If it is fed AC then its capacitor voltage swings positive then negative then positive then negative etc. But you can also feed it AC with DC on it then its DC voltage swings more then less then more then less etc.in lc circuit if you have one capacitor and one resistor parallel to it you do not have any cycles i mean in positive side of cap never negative sign will be created.
You make no sense.but if I replace res by inductor for reason of resonance effect . here magnetic field converts to static and vice versa
Please do not talk about feedback unless you say if it is positive feedback to make an oscillator or if it is negative feedback to reduce the gain of an amplifier.if there was not resistance feedback is also not required in ideal mode
You make no sense.this device also with a low resistance can produce at least one cycle of sin wave by lowering amplitude
The four RC phase shifts add up to 180 degrees of phase shift (three RC phase shifts can also add up to 180 degrees) and the transistor is inverting so it also produces 180 degrees of phase shift.but when you have tree caps and 4 res like BradtheRad image (without other devices on image just caps and res
and if first cap of the left has initial value you have wave that has positive and negative sign but that is not sin wave it is just a wave with one cycle and we can continue it with feedback I also tested this first step without feedback and get my result
When it is not clipping then the output is a single frequency. A sinewave is a single frequency. A squarewave, triangle wave and sawtooth wave have many additional harmonic frequencies.please tell me what is the physical reason that there must be a sin wave instead of other wave mode ?
I speak, read and write only in English. Your English and spelling are pretty bad but I think I understood about half of your text.if in any piece of my text is any wrong please say .
ُSorry if I can not express my question betterI speak, read and write only in English. Your English and spelling are pretty bad but I think I understood about half of your text.
if your mentions that it is not Intelligible (I do not know the mean of this sentence my native language is not English )You make no sense.
but if I replace res by inductor for reason of resonance effect . here magnetic field converts to static and vice versa
if there was not resistance feedback is also not required in ideal mode
this device also with a low resistance can produce at least one cycle of sin wave by lowering amplitude
The four RC phase shifts add up to 180 degrees of phase shift (three RC phase shifts can also add up to 180 degrees) and the transistor is inverting so it also produces 180 degrees of phase shift.
When the output is fed to the input then the total feedback is 360 degrees of positive feedback. Then the circuit oscillates at the frequency that the RC phase shifts add up to 180 degrees.
You are always taking about phase and positive and negative feedb I know them .When it is not clipping then the output is a single frequency. A sinewave is a single frequency. A squarewave, triangle wave and sawtooth wave have many additional harmonic frequencies.
ُHere I can not see any physical reason, for this wave to be Sinusoidal. Please just say me the physical reason of this phenomenon.
The physical reason is that the operation of the circuit is described by an ordinary differential equation with constant coefficients.
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