Jul 16, 2013 #1 P p.mahen Junior Member level 1 Joined Jul 13, 2013 Messages 16 Helped 1 Reputation 2 Reaction score 1 Trophy points 3 Activity points 95 Can anyone help me on this question A 120 ohms resistor is connected in series with a capacitive reactance of 160 ohms. Determine the current flow when the circuit is connected to 200V AC supply?
Can anyone help me on this question A 120 ohms resistor is connected in series with a capacitive reactance of 160 ohms. Determine the current flow when the circuit is connected to 200V AC supply?
Jul 16, 2013 #2 P pebe Advanced Member level 4 Joined Dec 1, 2008 Messages 116 Helped 18 Reputation 36 Reaction score 18 Trophy points 1,298 Location Scotland Activity points 1,893 The answer to this question is 1Amp
Jul 16, 2013 #3 P p.mahen Junior Member level 1 Joined Jul 13, 2013 Messages 16 Helped 1 Reputation 2 Reaction score 1 Trophy points 3 Activity points 95 How did you drive this answer?.. can you please show me the steps
Jul 16, 2013 #4 C chuckey Advanced Member level 6 Joined Dec 26, 2010 Messages 4,854 Helped 1,309 Reputation 2,624 Reaction score 1,281 Trophy points 1,393 Location Southampton and holiday cottage in Wensleydale (UK Activity points 31,695 Impedance = square root of 120 squared + 160 squared = 200 ohms. I = V/Z = 200/200 = 1A frank
Jul 16, 2013 #5 P p.mahen Junior Member level 1 Joined Jul 13, 2013 Messages 16 Helped 1 Reputation 2 Reaction score 1 Trophy points 3 Activity points 95 chuckey said: Impedance = square root of 120 squared + 160 squared = 200 ohms. I = V/Z = 200/200 = 1A frank Click to expand... Thank you, Now I understand Regards Prem
chuckey said: Impedance = square root of 120 squared + 160 squared = 200 ohms. I = V/Z = 200/200 = 1A frank Click to expand... Thank you, Now I understand Regards Prem