bomber
Newbie level 3
Could you tell me how can I prove the equality
N
∑ C(N,j)×C(M,n-j)=C(N+M,n)
j=0
In probability books it is said that (in hypergeometric distribution) this equality is well known but I couldn't prove this equality.
One addition information:
a hint has been given :
use the identity of:
(1+t)^(N+M)=((1+t)^N)*((1+t)^M)
thanks for replies....
N
∑ C(N,j)×C(M,n-j)=C(N+M,n)
j=0
In probability books it is said that (in hypergeometric distribution) this equality is well known but I couldn't prove this equality.
One addition information:
a hint has been given :
use the identity of:
(1+t)^(N+M)=((1+t)^N)*((1+t)^M)
thanks for replies....
