Re: the Rout in Nmos?
I think there is a basic confusion. When a transistor be it NMOS or PMOS is in saturation there are 2 output resistances associated with it, first you should get that distinction clear.
One resistance is tha large signal resistance, which as arunmit tried to explain is a low value of like 50 ohms for NMOS and 150 ohms for PMOS, when the transistor is ON. This resistance can be looked at equivalently as :
Rout (Large Signal) = Vds / Ids,
where Vds is the DC biased voltage across the transistor when it is "ON" and Ids is the biasing current through it. This resistance is quite low.
The second resistance associated with a transistor in saturation, which is of main interest in Analog circuit design is the small signal output resistance. This resistance is defined as:
Rout (small signal) = δVds/δIds
which for example looking at the drain of the transistor in a common source configuration is ro, which is a very high value, which allows the transistor to behave as a good current source (for small signals !!).
This small signal output resistance is approximately equal to:
where λ is the channel length modulation factor. Comparing NMOS and PMOS transistors λ for a NMOS transistor is lower than that of a PMOS for the same biasing Ids and Vds, this can be understood by considering this:
so this means that if the NMOS and PMOS transistors are identical in dimensions and have same biasing ΔL for an NMOS is lower than that for a PMOS. And this makes sense because for the same Vgs an NMOS has a larger current than a PMOS because of its higher mobility therefore when both are in saturation such that
Ids (NMOS) = Ids (PMOS) this means that
|Vgs| (NMOS) < |Vgs| (PMOS)
thus this means that
|Vgd|(NMOS) < |Vgd| (PMOS) for same |Vds| across NMOS and PMOS
hence ΔL for NMOS will be lesser than that of PMOS for the same biasing, hence λ for NMOS is lesser than that of PMOS for same biasing and therefore the small signal output resistance is larger for the NMOS and it is a better current source at the same biasing and dimensions.
I hope this was helpful.