Hi note that \[rect(\frac{t}{T})\] is \[1\] for \[[-\frac{T}{2},\frac{T}{2}]\]. \[rect(\frac{t}{T}-1)\] is just shifted version of original signal \[rect(\frac{t}{T})\] by \[\frac{1}{2}\] to the left. So the signal will be \[1\] for \[[-frac{T}{2}+\frac{1}{2},rac{T}{2}+\frac{1}{2}]\]. Hope you got it.
thnx
purna!
Added after 47 seconds:
Hi note that \[rect(\frac{t}{T})\] is \[1\] for \[[-\frac{T}{2},\frac{T}{2}]\]. \[rect(\frac{t}{T}-1)\] is just shifted version of original signal \[rect(\frac{t}{T})\] by \[\frac{1}{2}\] to the left. So the signal will be \[1\] for \[[-\frac{T}{2}+\frac{1}{2},\frac{T}{2}+ \frac{1}{2}]\]. Hope you got it.
thnx
purna!
Added after 1 minutes:
Hi note that \[rect(\frac{t}{T})\] is \[1\] for \[[-\frac{T}{2},\frac{T}{2}]\]. \[rect(\frac{t}{T}-1)\] is just shifted version of original signal \[rect(\frac{t}{T})\] by \[1\] to the left. So the signal will be \[1\] for \[[-\frac{T}{2}+1,\frac{T}{2}+ 1]\]. Hope you got it.
thnx
purna!