Question about maximum byte send without exhausting sequence number (TCP)

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danesh

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guys,

having some doubt on tcp hope someone can help me understanding it. Assume L byte is send from node A to B. Assume MSS=1460 byte and sequence number feild has 4bytes. How can i calculate the maximum L value so the sequence number are not exhausted? thanks guys. apreciate your help.
 

TCP

4 bytes = 4*8 =32 bit meaning there will be 2^32 sequence numbers, and since the window should be less than 1/2 * 2^32, i.e. 2^22, so L = 1460 * 2^22 =...bytes
 

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