samy555
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Filtering. C3 will limit the high frequency response, C2 will limit the low frequency response.
Keith.
IC1A and IC1B operate as an filter f=1.59HzHi
I know that the first IC1A operate as an amplifier,
maybe it's sensors with integrated controller?When someone moves in front of the PIR, the frequency of the output signal will be small, about 1 Hertz or so.
But the resulting amplitude of that output signal will be up to 3 volts peak- as datasheets said.
First and second stage are identical, but first is non inverting.Gain define R4/R3 or R8/R5 ~100Let's focus on the first stage, is it operate as a filter, amplifier or both?
What made the designer compelled to put that first stage?
Yes, it is true.Are my calculations in post # 3 are true and what is your comment?
I found one:thank you very much
please point me to a site talking about using op-amp as a band pass filter to see how to design mine for other voltage amplification, low cutoff freq and high cutoff freq
thanks a lot
Yes. It is in detail described in manual. Post #7my questions are:
1) Are D1 and D2 for voltage reference?
2) why the first stage was noninverting and the second inverting?
Ok, thanksFirst stage is non inverting for high impedance, required by sensor.
I think C4 removes the DC component by first stage.Second stage is inverting for removing the DC component by first stage,
If the power supply was 12 volts, what will be the output voltage at pin7?and set output DC=U/2 by window comparator.
What can happen if you remove D3 &D4?I shall tell at once - D3 and D4 are logical OR for high level comparator output
Yes, of course, but do not forget that it is also the part of the filter. Two in one.I think C4 removes the DC component by first stage.
IC1B will have positive feedback and potencial output 7 will be near ground.What would happen if interchaning pin5 and pin6 of IC1B?
At pin7, pin5 and at pin6 voltage will be Usupply/2=6V/. It is defined to divider R6, D1, D2, R7.If the power supply was 12 volts, what will be the output voltage at pin7?
Outputs IC1C and IC1D will compete among themselves and on input IC2 will be not defined voltage.What can happen if you remove D3 &D4?
Sorry. I am forget.Attached file fails and I get the following message:
Put onSo far I could not Carry simulation, the same error massage appear, I hope you give me the specific steps that I must do so runs the program.
I do not understand what in the square "PIR sensor" attached base of the transistor.Secondly, I want to tell me what's wrong with using the following simple circuit?
the square "PIR sensor" is the PIR with 3 pins, it is as in the schematic Post #1I do not understand what in the square "PIR sensor" attached base of the transistor.
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