i think you need something like this. i can only tell you that the time constant of a capacitor tc = C*R, like n this circuit.
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or maybe you need something like this:
**broken link removed**
If the pulse width and amplitude are fixed then why do you need to delay it and what are you doing with the resulting signal? If the pulse characteristics are always the same then there is no need for an analogue delay - it could be digital in that you could just reproduce the signal 0.5 seconds later. Assuming the signal is not of infinite impedance you could possibly self power a CMOS circuit from the signal itself.
You can delay a signal any amount with a lumped transmission line approach but the number of stages required depends on the incoming pulse width and the delay required. I have use them occasionally in the past and you can probably still buy ready made ones, although they will certainly be for shorter delays than 0.5s
www.rhombus-ind.com/dlcat/app1_pas.pdf
Keith.
Keith.
Use a Schottky diode from the pulse to charge a capacitor which is then used as the power supply to some CMOS circuity. The CMOS circuit needs to be a very low power monostable based circuit which produces a 10ms pulse after being powered (or detecting the incoming pulse). The exact circuit would depend on the source impedance of the signal and repetition rate of the pulses.
I have done a similar thing with a signal with 100k ohm source impedance. I used it to charge a capacitor and supply a low power consumption dual opamp (LMC6442) which takes 0.95uA per amplifier. There are probably better ones now - the LPV521 takes only 0.35uA for example.
There are low power comparators as well which would be suitable for making a monostable - you just need to make sure the resistors you use are considerably larger than the signal source impedance.
Keith.
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