abeja0123
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SQRT(a²) = |a| (absolute value of a)
so √[(2+2)-(9/2)]² = √[5-(9/2)]²
becomes |(2+2)-(9/2)| = |5-(9/2)|
and not (2+2) - 9/2 = 5 - 9/2
here is one that works better:
-20=-20 (it is fact)
16-36=25-45 (16-36=-20,25-45=-20)
4^2-36 = 5^2-45 (4^2=16,5^2=25)
4^2-36 = 5^2-45
4^2-2.4.9/2 = 5^2-2.5.9/2 (2.4.9/2=36,2.5.9/2=45)
4^2-2.4.9/2 +(9/2)^2 = 5^2-2.5.9/2 +(9/2)^2 (adding both the sides (9/2)^2
[4-(9/2)]^2 = [5-(9/2)]^2 (let 4=a,9/2=b)
4-(9/2) = 5-(9/2)
4 = 5
2+2 = 5
---------- Post added at 11:35 ---------- Previous post was at 11:34 ----------
here's another one
Let x be a non-zero number, and set y=x. Thus:
x = y
x^2 = xy
x^2-y^2 = xy-y^2
(x+y)(x-y) = y(x-y)
x+y = y
2y = y
2 = 1
1 = 0
Now since 2+2 = 2+2+0 and we apply the lemma proof so that 0 = 1, 2+2+0 = 2+2+1 =5
THEREFORE
2+2 = 5
It's so weird title and I am not getting how do you solve this type of problems. I think you should express 3rd line in well matter and why we go through this equation?Start with: -20 = -20
Which is the same as: 16-36 = 25-45
Which can also be expressed as: (2+2) 2 (9 X (2+2) = 52) 9 X 5
Add 81/4 to both sides: (2+2) 2 (9 X (2+2) + 81/4 = 52) 9 X 5 + 81/4
Rearrange the terms: ({2+2}) 9/2) 2 = (5-9/2) 2
Ergo: 2+2 - 9/2 = 5
Hence: 2 + 2 = 5
Here's a formula known as Euler's equation. It's for real and it is paradoxical.
E is the well known important constant which is the base of natural logarithms.
I is the square root of minus 1.
https://betterexplained.com/articles/intuitive-understanding-of-eulers-formula/
Also, just for the fun of it, calculate i^i. That neatly ties i, pi, and e together.
can you prove it out and state how they are tied to each other
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