Mizan.Bangladesh
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I don't clearly hear "high-side switch" from the post. "drive a Source from the mosfet drain" is at least ambiguous.Since you'll be using the MOSFET as a high-side switch, you need to use the IR2110 as a high-side driver.
I don't clearly hear "high-side switch" from the post. "drive a Source from the mosfet drain" is at least ambiguous.
In case a high side switch is actually meant, I see a possible problem with the suggested configuration. The IR2110 bootstrap circuit will only work, if the load is periodically shorted to ground. This doesn't necessarily work with all kinds of load, e.g. the mentioned battery.
In your circuit, will the drain of the MOSFET be connected to +ve and the load between source and ground? If so, you have to use high-side.
Or
In your circuit, will the source of the MOSFET be connected to -ve and the load between +ve and drain? If so, you have to use low-side.
:
As shown, the second circuit dumps the inductor's stored energy to the transistor, forcing it into avanlanche breakdown and possibly exeeding it's maximum ratings. The circuit efficiency isn't better than a linear regulator in this case. It should be supplemented by a diode between drain and V+ to a buck converter.
The inductor can be also placed between drain and battery-, reducing output PWM noise.
Keep in mind the maximum duty cycle. Connect a 0.1uF ceramic capacitor in parallel to the bulk capacitor.
why i have to Connect a 0.1uF ceramic capacitor in parallel to the bulk capacitor.??
Please clear me .
thanks
Keep in mind the maximum duty cycle. Connect a 0.1uF ceramic capacitor in parallel to the bulk capacitor.
You can use one of the two configurations:
As you can see, the low side configuration (the bottom one) will require less parts. However, in this configuration there is no common ground with the load. For the high side configuration (the top one), while there are more parts, you have the advantage of common ground (if you need it).
Hope this helps.
Tahmid.
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