Continue to Site

Welcome to EDAboard.com

Welcome to our site! EDAboard.com is an international Electronics Discussion Forum focused on EDA software, circuits, schematics, books, theory, papers, asic, pld, 8051, DSP, Network, RF, Analog Design, PCB, Service Manuals... and a whole lot more! To participate you need to register. Registration is free. Click here to register now.

Primary and secondary turns calculation for 0-6v 500mA Transformer

Status
Not open for further replies.

Ramana Madishetti

Junior Member level 1
Junior Member level 1
Joined
Sep 1, 2013
Messages
19
Helped
1
Reputation
2
Reaction score
1
Trophy points
3
Location
karimnagar
Activity points
139
Please suggest me,

Here am using 0-6 V 500 mA transformer. I need theoretical calculation for change in output voltage with the change in input voltage.

here i have the formula for Primary turn Np=(Vp*10^8)/4*1.11*Fo*AC*Bmax

Where Bmax=maximum flux density in guass
AC= effective core area in cm^2 (convert from m^2)
Fo= Input frequency (50 Hz)
Np= primary turns.

I dont know what is AC an Bmax for 0-6 V 500 mA transformer.

Thanks & regards
 

Status
Not open for further replies.

Part and Inventory Search

Welcome to EDABoard.com

Sponsor

Back
Top