The .7 and .07 ohms form a 10-to-1 resistor divider.
You can hook up low-ohm resistors in parallel to obtain these values.
To obtain .07 ohms using copper wire, it can be made from 8 inches of 30 AWG. Or 5 inches of 32 AWG. Etc.
The 0.7 ohm must carry 3 amps, so thin wire is not workable.
Do you have a 1 ohm, 5 or 10 watt type? (Probably rectangular sandstone?) Or 0.82 ohm?
If it's like one that I broke apart, you can gouge or ***** or break the coating (carefully) and expose a resistive wire inside.
It may not accept lead solder, but maybe you can use some kind of solder or welding, to attach your positive supply wire to the resistive element, 1/10 length from the end. That would be the same as what you need.