Dec 13, 2014 #1 K kenambo Full Member level 6 Joined Feb 26, 2012 Messages 393 Helped 52 Reputation 104 Reaction score 48 Trophy points 1,308 Location India Visit site Activity points 3,859 Hi all what will happen my forward applied bias voltage reaches or exceeds the built-in potential.. Is it possible to entirely vanish the depletion region in a diode? according to equation barrier voltage = q(Vbi-Vapplied) if vbi=Vapplied barrier = 0V am i right?
Hi all what will happen my forward applied bias voltage reaches or exceeds the built-in potential.. Is it possible to entirely vanish the depletion region in a diode? according to equation barrier voltage = q(Vbi-Vapplied) if vbi=Vapplied barrier = 0V am i right?
Dec 13, 2014 #2 D dick_freebird Advanced Member level 7 Joined Mar 4, 2008 Messages 9,356 Helped 2,345 Reputation 4,711 Reaction score 2,610 Trophy points 1,393 Location USA Visit site Activity points 74,148 Yes, once you inject forward current there is no depletion anymore. There are carriers moving through where it used to be.
Yes, once you inject forward current there is no depletion anymore. There are carriers moving through where it used to be.
Dec 14, 2014 #3 D.A.(Tony)Stewart Advanced Member level 7 Joined Sep 26, 2007 Messages 9,915 Helped 1,856 Reputation 3,713 Reaction score 2,416 Trophy points 1,413 Location Richmond Hill, ON, Canada Visit site Activity points 63,325 kenambo said: Hi all what will happen my forward applied bias voltage reaches or exceeds the built-in potential.. Is it possible to entirely vanish the depletion region in a diode? according to equation barrier voltage = q(Vbi-Vapplied) if vbi=Vapplied barrier = 0V am i right? Click to expand... Vbi = Vt*ln(Na*Nd/ni²)= = Built-in Potential Barrier .... Vbi≠0 Va = Applied forward bias voltage
kenambo said: Hi all what will happen my forward applied bias voltage reaches or exceeds the built-in potential.. Is it possible to entirely vanish the depletion region in a diode? according to equation barrier voltage = q(Vbi-Vapplied) if vbi=Vapplied barrier = 0V am i right? Click to expand... Vbi = Vt*ln(Na*Nd/ni²)= = Built-in Potential Barrier .... Vbi≠0 Va = Applied forward bias voltage
Dec 15, 2014 #4 K kenambo Full Member level 6 Joined Feb 26, 2012 Messages 393 Helped 52 Reputation 104 Reaction score 48 Trophy points 1,308 Location India Visit site Activity points 3,859 So the immobile charge carriers of p-side and n-side got their respective holes and electrons when we apply a sufficient forward voltage. is it correct?
So the immobile charge carriers of p-side and n-side got their respective holes and electrons when we apply a sufficient forward voltage. is it correct?