rajaram04
Advanced Member level 3
- Joined
- Jun 17, 2012
- Messages
- 871
- Helped
- 6
- Reputation
- 12
- Reaction score
- 5
- Trophy points
- 1,298
- Location
- earth
- Activity points
- 7,687
Hello sir
May you attach the schematic which you have built ? it is pretty hard to answer without any kind of schematic .i am using LM317 as voltage regulator to get a 9 volts o/p & at the I/p i am applying 18 volt dc out from a bridge rectifier
I followed all type of diagrams available all around but the output level is going down (with no load & too load condition)
the whole assembly is on bread board
please help me in solving the issue
Hi rajaram04
How you are so sure that only sirs will try to answer you ? ha ha ( of course i'm male but sometimes girls will try to answer here so use a common word rather than that like hi all )
Anyway ,
May you attach the schematic which you have built ? it is pretty hard to answer without any kind of schematic .
But i guess you built it wrongly perhaps you maybe your capacitors are dealing with problem or if all of em ar right probable your IC is came from china !
Best Wishes
Goldsmith
He said the voltage dropped even when the LM317 had no load so it was not getting too hot.
Maybe he made his own resistors with pencil lead or something. Remember "carbon composition" resistors that changed their value if you looked at them?
Maybe he made his own resistors with pencil lead or something. Remember "carbon composition" resistors that changed their value if you looked at them?
So it was the pot that changed its resistance that slowly reduced the voltage.
The datasheet for the expensive LM117 and less expensive LM317 says that the output voltage will rise for some of them without a load if the current in R1 is less than 5mA for the LM117 or 10mA for the LM317. The resistor has 1.25V across it so the maximum value for an LM317 is 1.25V/10mA= 125 ohms, use 120 ohms. You can use 220 ohms with an LM117.
So it was the pot that changed its resistance that slowly reduced the voltage.
The datasheet for the expensive LM117 and less expensive LM317 says that the output voltage will rise for some of them without a load if the current in R1 is less than 5mA for the LM117 or 10mA for the LM317. The resistor has 1.25V across it so the maximum value for an LM317 is 1.25V/10mA= 125 ohms, use 120 ohms. You can use 220 ohms with an LM117.
You have capacitors and diodes that are not needed for a charger voltage regulator.
The datasheet for the LM317 has a simple current regulator circuit.
The datasheet for the LM317 shows that if the input to output voltage is at least 3V and the input voltage varies 10V then the output voltage typically varies only 1mV. It is called Line Regulation.
The datasheet explains that the Line Regulation is much worse if the resistor connected to the output pin has series wiring and/or the series resistance of a breadboard contact which is probably your regulation problem.
You do not need the third regulator because the MINIMUM INPUT (do you know what this is?) voltage for the current regulator is +9.65V. Use +12V to make sure that the input never goes below 9.65V.
Maybe the smoothing capacitor value of the bridge rectifier is too low and causes the voltage to drop too low 100 times per second. Here is a sketch of the waveforms from a bridge rectifier and if the smoothing capacitor value is too low then the voltage can drop to zero volts.
I explained in your personal message that the 1A current regulator always has 1.2V to 1.25V across the resistor from the Output to the Adj pin. The resistor value is 1.25V/1A= 1.25 ohms.
It heats with 1.25v x 1A= 1.25W so a 1W resistor will burn away. Use a 2W resistor that will not get too hot.
We use cookies and similar technologies for the following purposes:
Do you accept cookies and these technologies?
We use cookies and similar technologies for the following purposes:
Do you accept cookies and these technologies?