xIce
Newbie
Hello everyone,
For the first time in my life, I am approaching Analog Design and my actual task is to to get an output impedance equal to 1MegaOhm for a Low Voltage Cascode Current Mirror;
The current is 20uA, the four MOSFETs involved in the circuit are pretty much the same when it comes to Cox, modulation channel length and other parameters.
So basically the only thing that I need to change, from what I understood, is the ratio W/L of the MOSFETs; Of course, since I want the output current to match the reference current, the ratio W/L of the two MOSFETs involved in the cascode, the upper ones basically, needs to be the same and the same goes for the W/L of the mirror MOSFETs.
I have noticed that decreasing the length of the mirror MOSFETs allows me to gain a higher output impedance, like right now the maximum value that I got is 738 kOhm by using W/L=20/0.50 for the Mirror MOSFETs and W/L=20/1 for the Cascode Mosfets;
I am not sure if I understood how the ratio W/L should change the output impedance. Could anyone explain it to me?
Kind regards and thanks to everyone who is going to answer me
For the first time in my life, I am approaching Analog Design and my actual task is to to get an output impedance equal to 1MegaOhm for a Low Voltage Cascode Current Mirror;
The current is 20uA, the four MOSFETs involved in the circuit are pretty much the same when it comes to Cox, modulation channel length and other parameters.
So basically the only thing that I need to change, from what I understood, is the ratio W/L of the MOSFETs; Of course, since I want the output current to match the reference current, the ratio W/L of the two MOSFETs involved in the cascode, the upper ones basically, needs to be the same and the same goes for the W/L of the mirror MOSFETs.
I have noticed that decreasing the length of the mirror MOSFETs allows me to gain a higher output impedance, like right now the maximum value that I got is 738 kOhm by using W/L=20/0.50 for the Mirror MOSFETs and W/L=20/1 for the Cascode Mosfets;
I am not sure if I understood how the ratio W/L should change the output impedance. Could anyone explain it to me?
Kind regards and thanks to everyone who is going to answer me