Operate solenoid from low voltage source

[heryrg]

Hello guys,
I'm a newb here so please pardon any silly mistakes i make.
I am designing a circuit to drive a latching solenoid. It will work something like this:
I have a constant voltage signal (low voltage and low current) 700mV to 950mV.
When the voltage value will be 894mV (as of now) i want to apply a 38v signal to the solenoid.
When the voltage drops to 811mv (as of now) i want to apply a -12v signal to the solenoid.

I think i need to use the H-bridge circuit to drive a latching solenoid, some sort of high voltage amp for the solenoid voltage, and transistors for sensing the voltage and applying a signal at the right time.

I would really appreciate any help from you guys because im kinda stuck right now.

thanks

 

[FvM]

Do you actually mean "operate from" or just "operate depending on"?
In other words, do you have a high voltage supply?

 

[heryrg]

I don't have a high voltage power supply. It's battery powered with 2.4 or 3.6v, not 100% sure yet.
I've played with the solenoid today and found out that the voltage needed is actually much less then the rating. To activate it in and out i need around +/-10v.

I guess my real question here is how do i transform a 100mV voltage difference to +10v and -10v? 900mv sends +10v 800mv sends -10v
thanks

 

[heryrg]

Can anybody help me out??

 

[FvM]

I understand, that you have two different problems:
- processing the 700mV to 950mV in put signal
- generating a high voltage from a 2.4 or 3.6V supply

As a general answer, the first involves a comparator circuit, the second a boost converter respectively an inverting boost converter.
Both are standard electronics building blocks.