Hi,
I expect the 1.2mA to be the nominal current that needs to be applied to the FAULT pin.
So, in order to SAFELY activate the OVP function I´d apply "1.2mA PLUS SOME MARGIN"
Let´s say your external circuit activates at about 36V.
Let the voltage across CE of Q4 be 0.5V
so the current through R32 is (36V - 0.5V - 3V) / 27k = 1.20mA
The extra current through R23 is 3V / 22k = 0.14mA
leaves a pin current of only 1.06mA
In my eyes not a safe level to activate OVP.
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The max pin voltage is 5.5V ... thus you may apply (5.5V - 1.35V) / 1.35kOhm = 3.07mA (nom)
--> I see no problem in driving the PIN with 1.5mA...2.0mA (at least 20% margin)
If you still want to protect the pin you could add an external 4.7V zener.
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Disclaimer: I did not read the complete datasheet. Thus I may have missed some informations.
Klaus