this is the basic concept..i have designed the circuit to amplify the 0.002v to 5 v..
according to the formula for non inverting amplifier the Rf and Rin values are 1.5M ohms
and 1K..to produce 5v as output..
i have simulated this circuit in Ltspice.
but i get the waveforms like this.what is the reason for this?
can u suggest me where i did the mistake?
This IC has a gain/bandwidth product of 80 MHZ, so at a gain of 2500, it will have a bandwidth of 80 KHZ/2.5 ~ 32 KHZ. Reduce your time base speed on the CRO display to get a meaningful result. use two in series each with a gain of 50, so overall gain is the same but the bandwidth will be 1.3 MHZ of each, so the overall bandwidth will be more like, 500 KHZ.
Frank
No. Please look at the datasheet for the LT1800 rail-to-rail opamp.
With a 5.0V supply and no load its output can swing from 0.02V to 4.98V. Its negative feedback resistor is its load which is such a high value that it will not reduce the maximum output voltage.
No. Please look at the datasheet for the LT1800 rail-to-rail opamp.
With a 5.0V supply and no load its output can swing from 0.02V to 4.98V. Its negative feedback resistor is its load which is such a high value that it will not reduce the maximum output voltage.
No. Please look at the datasheet for the LT1800 rail-to-rail opamp.
With a 5.0V supply and no load its output can swing from 0.02V to 4.98V. Its negative feedback resistor is its load which is such a high value that it will not reduce the maximum output voltage.