moonnightingale
Full Member level 6
The question says
The interferer
is on with probability .25 and off with probability .75.
The average transmit power is 10 mW,
And solution says
0.75P1 + 0.25P2 = 10
and then he gives the answer
P1= 12.25 mW
P2=3.25mW
How he calculated P1 and P2
and P2 =3.25 mW
The interferer
is on with probability .25 and off with probability .75.
The average transmit power is 10 mW,
And solution says
0.75P1 + 0.25P2 = 10
and then he gives the answer
P1= 12.25 mW
P2=3.25mW
How he calculated P1 and P2
and P2 =3.25 mW