I have doubt will something like this work?
Can MCU AT89S51 source current approx 20mA to drive the displays?
I thought I could achieve necessary source current for display just using the Ohm law (5V volts and required current resistor to get current I need
So, if full bright segment need about 20mA, and with this solution I cant get "bigger" current than >5mA then i could use smallest resistor I have for segments?
To be exact, the kirchoff law is what you will use, because the drop voltage across the LED segment should be accounted, which is also depentent of the color of the LED.
You did not mentioned yet the P/N of the 7-seg display device; there are variants offering high brigh with smaller currents.
Don't believe you read it thoroughly. Consider the meaning of Voh and Iil specifications. Source current is a few 10 µA only.In datasheet of at89S51 I did not find anything related for max source current on pins..?
Don't believe you read it thoroughly. Consider the meaning of Voh and Iil specifications. Source current is a few 10 µA only.
In fact, 8051 can neither drive the segments nor BC548 or BC337 digit switch transistors.
Yes, you can add external pull-ups to increase the high current, e.g. to drive a digit transistor. According to output drive capability and maximum ratings, a resistor values down to about 2.5k are feasible. You still need additional driver transistors for the segment lines.
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