msp430 adc hex to decimal routine

msp430 bcd

hi,
can someone help me by giving a method or code( ) in c for converting a hex o/p of the 12bit ADC on the msp to a decimal number ??
i need to do some mul. and div etc. on that data before displaying it on the LCD.
any help will be appreciated.
thank you
sam

msp430 adc

What do you mean by "decimal number"? Is this BCD number?
In example, if you have 0x12 hexadecimally you want to change it to
BCD number: 0x18?
0x18 is decimal representation of 0x12 hexadecimal number.

C routine for that conversion (hexadecimal must be less than 0x64):


unsigned char hex2bcd(unsigned char hex)
{
unsigned char bcd;

bcd = ((hex / 10) << 4) + (hex % 10);
return(bcd);
}//hex2bcd

binary to ascii on msp430

hi,
thanks for the reply.
like i had told before , i need it for the adc. so
it should be capable of taking from 0x00 to 0xFFF. i think ur routine is only for 0-100 decimal.
bye
thanks anyway, but i still need it so i am trying to buold one from the pic routine i have. :idea:
bye
sam

binary-to-bcd msp430

Hi,

To convert 12 bit number to decimal or ASCII try the code below

void hex2dec(unsigned adchex,unsigned value)
{
unsigned value[4];

for(i=0;i<4;i++)
{
value=adchex%10;
// value=adchex%10+0x30; //for ASCII presentation
adchex=adchex/10;
}
}

Hope it helps.

Regards,
George

hex2bcd c

hi,
what i wanted is not "hex representation" but hex to decimail conversion
ie 0xF44 (hex) = 3908(decimal)

here is the code for direct display on the built in LCD(msp430f435)


// binary to BCD file

void putdec_lcd(unsigned long binary)
{
unsigned char count=0;
union {
struct {
unsigned long low; //4 bytes
unsigned long high; //4 bytes
} lng;
unsigned char byte[8];
} cdec;

static unsigned char encountered_only_zeros;
signed char c;
unsigned char d;

//at least it prints '0' if it is zero, and doesnt skip all leading zeros!
if (binary==0) {
lcd_data[0]=lcd_data[1]=lcd_data[2]=lcd_data[3]=0;
return;
}

//implement the technique above
cdec.lng.low=binary;
cdec.lng.high=0; //12W / 2l

for (c=0;c<32;c++) {

//shift hi:lo <<1
d=cdec.byte[3];
cdec.lng.low<<=1;
cdec.lng.high<<=1;
if ( (d& 0x80)==0x80) cdec.byte[4]|=1;

for (d=4;d<7;d++) {
if ((cdec.byte[d]&0x0F)>=0x05) cdec.byte[d]+=0x3;
if ((cdec.byte[d]&0xF0)>=0x50) cdec.byte[d]+=0x30;
}
}


encountered_only_zeros=1; //for skipping leading zeros

for (c=15;c>=8;c--) {
d=cdec.byte[c>>1];
if ((c&1)==0) {
d&=0x0F;
}
else {
d&=0xF0;
d>>=4;
}
if (d>=8) d-=3;
if (d!=0) encountered_only_zeros=0;
if (encountered_only_zeros==0)
{lcd_data[count]=d;count++;}
}

if(count==3)
{
lcd_data[3]=lcd_data[2];
lcd_data[2]=lcd_data[1];
lcd_data[1]=lcd_data[0];
lcd_data[0]=0;
}
if(count==2)
{
lcd_data[3]=lcd_data[1];
lcd_data[2]=lcd_data[0];
lcd_data[1]=0;
lcd_data[0]=0;
}
if(count==1)
{
lcd_data[3]=lcd_data[0];
lcd_data[2]=0;
lcd_data[1]=0;
lcd_data[0]=0;
}

_NOP();

}

// bin to BCD ends here

this is the exact routine , with some changes of the one on www.microchipc.com
if someone can give me an improvement, they are welcome.
thanks
sam

hexadecimal to decimal in c

Hi,

Yes, I gave you decimal conversion, not hex presentation. You should use the program below (in your terms).

void putdecLCD(int binary)
{
for(i=0;i<4;i++)
{
lcd_data[3-i]=binary%10;
binary=binary/10;
}
}

Lets check it for your example

binary=3908;

1) i=0; lcd_data[3]=3908%10=8; binary=3908/10=390;

2) i=1; lcd_data[2]=390%10=0; binary=3908/10=39;

3) i=2; lcd_data[1]=39%10=9; binary=39/10=3;

4) i=3; lcd_data[0]=3%10=3; binary=3/10=0;

You can see that lcd_data array is correct.

Regards,
George

converting 12 bit counts to decimals

hi georgeM,
u dont seem to understand what i want .
i dont want to split 3980 to 3,9,8,0( by simple % operation)and display
but i want to convert a hexadecimal number into BCD , like on the windows acessories , calculator: type some hex num and goto decimal format, it gets converted. i want to do the same on the msp.
i hope uhave got it!!

now u see

12-bit unsigned binary to decimal

int BCDcode;
BCDcode=(lcd3<<12)+(lcd2<<8)+(lcd1<<4)+lcd0;