msp430 adc hex to decimal routine

[sam_manchali]

msp430 bcd

hi,
can someone help me by giving a method or code( ) in c for converting a hex o/p of the 12bit ADC on the msp to a decimal number ??
i need to do some mul. and div etc. on that data before displaying it on the LCD.
any help will be appreciated.
thank you
sam

 

[arturt134]

msp430 adc

What do you mean by "decimal number"? Is this BCD number?
In example, if you have 0x12 hexadecimally you want to change it to
BCD number: 0x18?
0x18 is decimal representation of 0x12 hexadecimal number.

C routine for that conversion (hexadecimal must be less than 0x64):


unsigned char hex2bcd(unsigned char hex)
{
unsigned char bcd;

bcd = ((hex / 10) << 4) + (hex % 10);
return(bcd);
}//hex2bcd

 

[sam_manchali]

binary to ascii on msp430

hi,
thanks for the reply.
like i had told before , i need it for the adc. so
it should be capable of taking from 0x00 to 0xFFF. i think ur routine is only for 0-100 decimal.
bye
thanks anyway, but i still need it so i am trying to buold one from the pic routine i have. :idea:
bye
sam

 

[GeorgeM]

binary-to-bcd msp430

Hi,

To convert 12 bit number to decimal or ASCII try the code below

void hex2dec(unsigned adchex,unsigned value)
{
unsigned value[4];

for(i=0;i<4;i++)
{
value=adchex%10;
// value=adchex%10+0x30; //for ASCII presentation
adchex=adchex/10;
}
}

Hope it helps.

Regards,
George

 

[sam_manchali]

hex2bcd c

hi,
what i wanted is not "hex representation" but hex to decimail conversion
ie 0xF44 (hex) = 3908(decimal)

here is the code for direct display on the built in LCD(msp430f435)


// binary to BCD file

void putdec_lcd(unsigned long binary)
{
unsigned char count=0;
union {
struct {
unsigned long low; //4 bytes
unsigned long high; //4 bytes
} lng;
unsigned char byte[8];
} cdec;

static unsigned char encountered_only_zeros;
signed char c;
unsigned char d;

//at least it prints '0' if it is zero, and doesnt skip all leading zeros!
if (binary==0) {
lcd_data[0]=lcd_data[1]=lcd_data[2]=lcd_data[3]=0;
return;
}

//implement the technique above
cdec.lng.low=binary;
cdec.lng.high=0; //12W / 2l

for (c=0;c<32;c++) {

//shift hi:lo <<1
d=cdec.byte[3];
cdec.lng.low<<=1;
cdec.lng.high<<=1;
if ( (d& 0x80)==0x80) cdec.byte[4]|=1;

for (d=4;d<7;d++) {
if ((cdec.byte[d]&0x0F)>=0x05) cdec.byte[d]+=0x3;
if ((cdec.byte[d]&0xF0)>=0x50) cdec.byte[d]+=0x30;
}
}


encountered_only_zeros=1; //for skipping leading zeros

for (c=15;c>=8;c--) {
d=cdec.byte[c>>1];
if ((c&1)==0) {
d&=0x0F;
}
else {
d&=0xF0;
d>>=4;
}
if (d>=8) d-=3;
if (d!=0) encountered_only_zeros=0;
if (encountered_only_zeros==0)
{lcd_data[count]=d;count++;}
}

if(count==3)
{
lcd_data[3]=lcd_data[2];
lcd_data[2]=lcd_data[1];
lcd_data[1]=lcd_data[0];
lcd_data[0]=0;
}
if(count==2)
{
lcd_data[3]=lcd_data[1];
lcd_data[2]=lcd_data[0];
lcd_data[1]=0;
lcd_data[0]=0;
}
if(count==1)
{
lcd_data[3]=lcd_data[0];
lcd_data[2]=0;
lcd_data[1]=0;
lcd_data[0]=0;
}

_NOP();

}

// bin to BCD ends here

this is the exact routine , with some changes of the one on www.microchipc.com
if someone can give me an improvement, they are welcome.
thanks
sam

 

[GeorgeM]

hexadecimal to decimal in c

Hi,

Yes, I gave you decimal conversion, not hex presentation. You should use the program below (in your terms).

void putdecLCD(int binary)
{
for(i=0;i<4;i++)
{
lcd_data[3-i]=binary%10;
binary=binary/10;
}
}

Lets check it for your example

binary=3908;

1) i=0; lcd_data[3]=3908%10=8; binary=3908/10=390;

2) i=1; lcd_data[2]=390%10=0; binary=3908/10=39;

3) i=2; lcd_data[1]=39%10=9; binary=39/10=3;

4) i=3; lcd_data[0]=3%10=3; binary=3/10=0;

You can see that lcd_data array is correct.

Regards,
George

 

[sam_manchali]

converting 12 bit counts to decimals

hi georgeM,
u dont seem to understand what i want .
i dont want to split 3980 to 3,9,8,0( by simple % operation)and display
but i want to convert a hexadecimal number into BCD , like on the windows acessories , calculator: type some hex num and goto decimal format, it gets converted. i want to do the same on the msp.
i hope uhave got it!!

now u see

 

[GeorgeM]

12-bit unsigned binary to decimal

int BCDcode;
BCDcode=(lcd3<<12)+(lcd2<<8)+(lcd1<<4)+lcd0;