Moving The bit value to array

[nayakajit87]

Dear all

I have digital IO which reads high(1) or LOW(0). I have created char buf which read the 1 byte of data thats 8 bits
Currently i am moving my data like this .Where i store the values like this

need simple code where i could able to move 0A into Buffer that buffer value to be move to ser_data[]
ser_data[3]=0X0A;
ser_data[4]=0XFF;
ser_data[5]=0XA0;
ser_data[6]=0XFF;

0A means -> 8 digital Io -> 0000 1010 this is value it read.This might change Io pin state changes. SImple code to move bit value to array to form byte

 

[betwixt]

I don't understand your question. Do you mean you want to convert 8 bits arriving one at a time into a byte?
If that is what you want, either use a UART if there is one or you can construct a shift register in software to assemble the bits together.

Brian.

 

[nayakajit87]

I have written simple code in arduino platform.

Here INF will store the digital status of Input configured. Now i wanted to move all 8 pin digital IO to ser_data[] buffer and print Ser_data to represent 8 bit

if all digital io read is FF means all input are 1 then

Ser_data= 0XFF where all bit represent like this

INPUT_T.INF1 = 1;
INPUT_T.INF2 = 1;
INPUT_T.INF3 = 1;
INPUT_T.INF4 = 1;
INPUT_T.INF5 = 1;
INPUT_T.INF6 = 1;
INPUT_T.INF7 = 1;
INPUT_T.INF8= 1;

Ser_data= 0X0A

INPUT_T.INF1 = 0;
INPUT_T.INF2 = 1;
INPUT_T.INF3 = 0;
INPUT_T.INF4 = 1;
INPUT_T.INF5 = 0;
INPUT_T.INF6 = 0;
INPUT_T.INF7 = 0;
INPUT_T.INF8= 0;

unsigned char ser_data[10];
#define LED D1

typedef union
{
  struct
  {
    unsigned INF1: 1;
    unsigned INF2: 1;
    unsigned INF3: 1;
    unsigned INF4: 1;
    unsigned INF5: 1;
    unsigned INF6: 1;
    unsigned INF7: 1;
    unsigned INF8: 1;
  };
  unsigned char INF1_9;
} INPUT_TYPE;

INPUT_TYPE INPUT_T;

void setup() {
  // put your setup code here, to run once:

  Serial.begin(9600);
  pinMode(0, OUTPUT);
  pinMode(D1, INPUT);

}

void loop()
{
  // put your main code here, to run repeatedly:

  if (digitalRead(0) == 1)
  {
    INPUT_T.INF1 = 1;

  } else
  {
    INPUT_T.INF1 = 0;
  }

  if (digitalRead(D1) == 1)
  {
    INPUT_T.INF2 = 1;
    Serial.println("Pin high");
  } else
  {
    INPUT_T.INF2 = 0;
    Serial.println("Pin LOW");
  }
  delay(1000);


}

 

[KlausST]

Hi,

I also don´t understand the question.
In my eyes you mix different problems.
1) to get a byte from 8 input pins (one complete 8 bit port)
2) to store a byte in an array
3) to trnsmit one byte of the array via UART

Please focus on one problem.

for 1):
Just reading whole port input state will give you the desired byte like 0x0A. No need to convert anything.

****
For further discussion: you should tell which microcontroller and which compiler you use.

Klaus