It doesnt matter what resistance isconnected to the supply untill a load is connected. Mean if you measure the voltage after connecting 56K or 100K to 9volts, the out put will be 9 volts. Cheers
It doesnt matter what resistance isconnected to the supply untill a load is connected. Mean if you measure the voltage after connecting 56K or 100K to 9volts, the out put will be 9 volts. Cheers
how can it be 9V,for example in this circuit,there u can see a 10k pot and the its output connected to 56K,the 10k varies the voltage to the varicap in order to change the capacitance,my doubt is how can i know the voltage supplied to BB139 when i change the 10K pot,thats my actual doubt!
Why didn't you post the question like your last post in the first place?
The 9V is not supplied to the 56k resistor. The 9V is connected to a 10k pot, then there is a 56k resistor connected to the slider. Looks totally different to me.
If we consider the other side of the 56k resistor (NOT the potentiometer side) as a high impedance for DC. Then there is no load on the potentiometer slider to ground (very high resistor + 56k = very high resistor). the DC-level is blocked on one side by the varicaps, on the other side by the 220nF capacitor.
So what is the voltage on the slider of a potentiometer when you connect the fixed resistor between 9V and GND?
When you turn the pot, its output voltage varies from 0V to 9V.
When the voltage fed to the varicaps changes from 0V to 9V then their capacitance changes that changes the tuned frequency.
how can it be 9V,for example in this circuit,there u can see a 10k pot and the its output connected to 56K,the 10k varies the voltage to the varicap in order to change the capacitance,my doubt is how can i know the voltage supplied to BB139 when i change the 10K pot,thats my actual doubt!
When you turn the pot, its output voltage varies from 0V to 9V.
When the voltage fed to the varicaps changes from 0V to 9V then their capacitance changes that changes the tuned frequency.
u said when the pot is turned around slowly, voltage to the wiper changes from 0V to 9V,but how can i know how much volt is passing through the pot!
with the help of voltmeter.......!please help me !
u said when the pot is turned around slowly, voltage to the wiper changes from 0V to 9V,but how can i know how much volt is passing through the pot!
with the help of voltmeter.......!please help me !
I think you mean to say..."so then measuring the volts passing to the varicaps can be measured by voltmeter" Yes...but the meter should have a high impedeance input or it will affect the readings. Mean as you connect the meter, the frequency will drift....Cheers