Continue to Site

Welcome to EDAboard.com

Welcome to our site! EDAboard.com is an international Electronics Discussion Forum focused on EDA software, circuits, schematics, books, theory, papers, asic, pld, 8051, DSP, Network, RF, Analog Design, PCB, Service Manuals... and a whole lot more! To participate you need to register. Registration is free. Click here to register now.

Measuring inductance from y-parameters in simulation

Status
Not open for further replies.

allanvv

Advanced Member level 4
Full Member level 1
Joined
Oct 23, 2010
Messages
108
Helped
14
Reputation
28
Reaction score
12
Trophy points
1,298
Location
USA
Activity points
2,078
I'm calculating 1/(w*imag(y11)) to view inductance. However, using two different equations gets different results at DC:

Red curve: -1/(2*pi*w*imag(Y11)
Blue curve: 1/(2*pi*w) * imag(1/Y11)

Why are they different? The blue one is correct at DC and doesn't have have huge spikes.

PnQi8.png

xwmuo.png
 

-1/imag(y) is generally different from imag(1/y). In fact y is a complex variable, we can represents as y=a+j*b then:

-1/imag(y) = -1/b
imag(1/y) = imag[1/(a+j*b)] = imag[(a-j*b)/(a²+b²)] = -b/(a²+b²)

-1/imag(y) = imag(1/y) if and only if a=0

since L=imag(Z)/(2*pi*f) and y=1/Z ==> L = imag(1/y)/(2*pi*f)
 
Thanks. Now I'm trying to use the regular definition of Q as -imag(y11)/real(y11) to get Q at resonance. However, isn't imag(y11) = 0 at resonance? How do you evalulate Q this way?

edit: Nevermind, I figured this out.
 
Last edited:

Status
Not open for further replies.

Part and Inventory Search

Welcome to EDABoard.com

Sponsor

Back
Top