This reference states that the resistance of wood for two pins 30mm apart is 4800MΩ (4.8GΩ) for wood with 8% moisture. If you want to measure a lower moisture level than than, you would need to be able to measure a higher resistance.
I can give you some help on the design but more in the way of suggestions and critique of what you are designing, rather than a complete design.
The simple approach is to measure the voltage across some high value resistors in series with the measurement value. I did a quick check at Digikey and they sell resistors up to 5GΩ in value. The voltage could be amplified by a FET type op amp which has a very high input impedance (such as
this), configured as a non-inverting amp.
Depending upon the accuracy you want, you will likely need to switch in different value series resistors and/or change the op amp gain to cover the full dynamic range. The switching would need to be done with very high impedance switches, such as small reed relays. The resistors, relays, and op amp input pin should probably be connected to Teflon standoffs to minimize leakage current.
The measurement process would be to apply the supply voltage to the series combination of the wood terminals and the sense resistor. You then read the sense resistor voltage value and the supply voltage with an A/D converter (could be an A/D built into the µP), and calculate the wood resistance from that. If the measured voltage is too high or too low, then the µP would need to change the sense resistor value and/or op amp gain until the reading is within the desired range.