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The circuit in fig1 has no DC block, so the 50 Ohm port impedance will load any DC voltage on that net. DC current will flow into the port.

The circuit in fig2 has the series capacitor that blocks DC from flowing into the 50 Ohm port impedance.

[QUOTE="volker@muehlhaus, post: 1790546, member: 543974"] The circuit in fig1 has no DC block, so the 50 Ohm port impedance will load any DC voltage on that net. DC current will flow into the port. The circuit in fig2 has the series capacitor that blocks DC from flowing into the 50 Ohm port impedance. [/QUOTE]

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