LT1073 use in practical circuits

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Barasha

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Hi all,

I have studied that LT1073 is a dc voltage amplifier. Doesn't the IC require external power supply if implemented practically.
 

Go back and study some more. This is a DC-DC converter, NOT an amplifier. You apply an input voltage, and, depending on the model, you get a constant output voltage.
 
Study the datasheet: http://cds.linear.com/docs/Datasheet/1073fa.pdf

LT1073 is a DC-DC switching converter that can be configured for step up (boost) or step down (buck) conversion.

You can find formulae, circuits, explanations and all required information in the datasheet.

Here is the description from page 1 of the datasheet:



Hope this helps.
Tahmid.
 
barry said:
Go back and study some more. This is a DC-DC converter, NOT an amplifier. You apply an input voltage, and, depending on the model, you get a constant output voltage.
Click to expand...
Hi barry,
Sorry i made a mistake.Actually i need it for the purpose of DC to DC conversion from about 1.5 volts to 12 volts.As the voltage is increased at the output i used the word amplification.

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Hi Tahmid,

Thanks for the link.I have studied the datasheet .It mentions that the inner circuit has some low power comparators but i have some doubts. Since I have not used the chip practically,i want to know how the single 1.5 volts supply will give the 12 Volt output
 

You can find the circuit on page 12.

The voltage is stepped up and provides a DC output of higher voltage than the input voltage with the help of the internal transistor, the inductor, (schottky) diode and the bulk capacitor. It operates as a boost converter.

https://en.wikipedia.org/wiki/Boost_converter
 

Thanks Tahmid. So voltage is increased while power remains constant.
 

Yes.

Input power = Output Power.

But, due to losses in the converter, some of the output energy will be converted to heat.

So, useable output power (to load) < Input power.
 
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