Continue to Site

Welcome to EDAboard.com

Welcome to our site! EDAboard.com is an international Electronics Discussion Forum focused on EDA software, circuits, schematics, books, theory, papers, asic, pld, 8051, DSP, Network, RF, Analog Design, PCB, Service Manuals... and a whole lot more! To participate you need to register. Registration is free. Click here to register now.

logic ofDriving compatability between DS1110S and 74ABT04

yefj

Advanced Member level 5
Advanced Member level 5
Joined
Sep 12, 2019
Messages
1,505
Helped
1
Reputation
2
Reaction score
5
Trophy points
38
Activity points
9,114
Hello , I am connecting 0-3.3V pulse as an input to DS1110S.
pullup current is 1mA pull down is 12mA also it was said that it could drive 10 74LS type loads as shown below.
because the pull up current is drastickly lower i think we need to use pull up resistor.
My load is 74ABT04 with input capactiance is 3pF.
1.what is the capacitance of typical 74LS device?
2.I was told that if i connect 74ABT04 to the output of DS1110S the i dont need pullup resistor between them.
Why is that? I know we have a formula I=CdV/dt.
How can we know that we dont need pullup resistor?
Thanks.
https://www.analog.com/media/en/technical-documentation/data-sheets/DS1110.pdf
https://assets.nexperia.com/documents/data-sheet/74ABT04.pdf

1722351367180.png


1722351386164.png


1722351413568.png
 
The DS1110S can usually drive logic levels suitable for devices like the 74ABT04 without needing an additional pull-up resistor, given the lower input capacitance and the drive capability of the DS1110S.
 
Hello, I am interested in the math logic:
1.what is the capacitance of typical 74LS device?
2.How can i see that it doesnt need the pullup threw the I=C*dV/dt formula?
Thanks.
 
Update:
My load capacticance (input of the 74ABT04) is 3pF
I need to deliver a pulse so it will reach V_IH.
pullup current of the DS1110S is 1mA.
my pulse width is 200ns with 10ns rise time so from the formula I=C*dV/dt
1mA=3pF*(X/10ns)
X=3Volts
so its enough.
The question is what do we do if we dont reach VIH value.
How pullup resistor can help use increase the pullup current?
Thanks.
 
Hello, I am interested in the math logic:
1.what is the capacitance of typical 74LS device?
2.How can i see that it doesnt need the pullup threw the I=C*dV/dt formula?
Thanks.
The math for TTL is always based on Io/Iin current ratios = 10 for the same TTL family and not based on capacitance. The input current is expected to be < = 15 pF (std) / 10 = 1.5 pF which is normal to be less than CMOS.

It is always with an input threshold of two Vbe drops or 1.4V nominal at room temp. which happens to be the average of Vil + Vih. (0.8+2.0) to cover extreme temperatures and tolerances.

The math for CMOS is based on Vol/Io = Zo for a driver to Vih min/max with "T" family being TTL compatible threshold ( average of 0.8 and 2.0) . No need to worry about Voh .

Thus driver impedance and load capacitance directly affect risetime.
The 74LS has 120 + Rce (<5) for Zoh to Cin = 3pF, thus Tau= RC= 450 ps thus for a
1722455408111.png

For the LS family 400 uA/ 40 uA = 10 same as DS1110 delay line

For the risetime from TTL to CMOS you might use the specs Ic = 400 uA , C = 3 pF and Vih = min = 2V for 74ABTxx but in reality, it depends Darlington hFE, 8k Rb from 5V and a rising Vout for declining current which starts by exceeding -400 uA. (-15mA min)

I believe the 5ns/V CMOS input slew rate limit is to avoid transition noise producing multiple output transitions. This may be marginal but I think OK.

For CMOS the input current, Iin is only 1 uAdc + CdV/dt =3pF*dV/dt max due to gate leakage.
 

LaTeX Commands Quick-Menu:

Part and Inventory Search

Welcome to EDABoard.com

Sponsor

Back
Top