there is a capacitive load that has a high power usage (about 250 w).
the output signal of the transformer is a square signal .
b-point expected signal is sin-wave .to convert a-point ( square signal) to the sin-wave (b-point) , an inductor is added to the circuit and of curese it's
we lined up with three types of inductor .
a green-blue toroid inductor with inductance of 1.3 mh .
output signal is:
which is very close to our desired signal.
but the problem is that with the green-blue toroid core , the toroid become very warm after 30s (about 90 celecius).
and two more inductor with black toroid and green toroid . with same inductance as (green-blue ( 1.3mh))
the output is:
but the cores are cool .
in what way , the black or green toroid can be used to have the output signal similar to the sine wave .
load(c) is a piezo
all core are same size 25-15-10
but core type are different as i mention above( green-blue, black, green),
green-blue toroid core are about 60 turn
black toroid core are 6 turn
however , i don 't know what the different core behavior is?
it seems green-blue toroid have high core loss
and black core have minimum core loss
how can i have black core inductor with same parameter?
Hot core means I^2*DCR=Pd is too high so you need higher C added to suppress harmonics and lower DCZ to reduce heat.
But without and complete schematic with all V, L, DCR, f, I on primary, secondary , we cannot help much.
Also purpose of piezo and mechanical load is useful to determine VA and W separately thus pf.
O.k., a piezo is no capacitive load at resonance frequency, you need to analyze the actual impedance. Secondly, it sounds unlikely that 6 turns make 1.3 mH.
Hot core means I^2*DCR=Pd is too high so you need higher C added to suppress harmonics and lower DCZ to reduce heat.
But without and complete schematic with all V, L, DCR, f, I on primary, secondary , we cannot help much.
Also purpose of piezo and mechanical load is useful to determine VA and W separately thus pf.