LC filter simualtion in HSPICE

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bharatsmile2007

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hi,,

i want to simualte LC filter in HPSICE:

below is the sp file for LC filter:

***LC Filter Transfer function***

.option post=2
* INPUT PARAMETERS:
Vu1 in 0 3.3 ac 1
* TRANSFER FUNCTION
Glowpass out 0 laplace in 0 1/1,0,0.136n
* ANALYSIS
.AC DEC 10 1 1000K

* VIEW RESULTS
.PLOT V(*)
.PROBE
.END
==============================================

when i simualate the same i get any error:

**warning** unknown analysis mode

**error** only 1 connection at node 0ut defined in subckt 0

================================================

can anyone tell me how to solve the problem?

Thanks
 

Well, it's not really an LC filter - no inductors or capacitors!

The line:

Glowpass out 0 laplace in 0 1/1,0,0.136n

has a syntax problem: 1/1 will not be allowed.

You have no load - hence the error. Add a resistor from OUT to node zero.

I am a bit puzzled by the error reference to a subcircuit as a G source isn't a subcircuit.

Keith.
 

Thanks for the reply...

I have TF for the circuit attached here...is 1/(1+s²LC)
L=12mH
C=11nF
i wanted to see the gain of it by ac sim....Cant i do the sim without connecting a load?
 

bharatsmile2007 said:
Thanks for the reply...

i wanted to see the gain of it by ac sim....Cant i do the sim without connecting a load?
Click to expand...

Some simulators will complain about floating nodes. As you are using a G source it will drive any load. If it was a real circuit then you could simple use a very large load say 1G ohm so it doesn't affect the circuit but keeps the simulator happy.

Keith.

Added after 1 hours 31 minutes:

The syntax of my simulator is different, but for Hspice I think it should look like the following:

Glowpass out 0 LAPLACE in 0 1 / 1 0 0.136n

The only differences with what you used are spaces instead of commas. Commas may be ok, but then I think the syntax might have to be

Glowpass out 0 LAPLACE in 0 1,/,1,0,0.136n

but I am not sure.

Keith.
 

Thanks keith1200rs...

i got simulation done when i connected the load and the syntax is correct it takes spaces and commas also...

thanks once again....
 

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