gonsays
Newbie level 5
![Newbie level 5](/styles/images/ranks/blevel2.gif)
Hello ![Smile :) :)](data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7)
I've been designing an OTA on CADENCE and I would like to perform the common centroid for the following transistors:
![m14_m11_schematic.PNG m14_m11_schematic.PNG](https://www.edaboard.com/data/attachments/53/53344-c442b1a5010062f08ddefebd34f83ebd.jpg)
The original dimensions:
W14=55um ; L14=0.55um
W11=27um ; L11=0.55um
New dimensions (dividing M14 in 4 transistors & M11 in 2 transistors) for each divided transistor:
W14'=W14/4=55um/4=13.75um ; L14'=L14=0.55um;
W11'=W11/2=27um/2=13.5um; L11'=L11=0.55um;
On the following figure you can check them on the layout:
![m14_m11.PNG m14_m11.PNG](https://www.edaboard.com/data/attachments/53/53345-12a256d560496242a1e4236d9f88276e.jpg)
What would be the best combination for the common centroid (with 6 transistors total)? Is there a problem with the dimensions (13.5um vs. 13.75um) between the pair? Should dummies be used?
Thank you very much in advance!![Smile :) :)](data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7)
I've been designing an OTA on CADENCE and I would like to perform the common centroid for the following transistors:
![m14_m11_schematic.PNG m14_m11_schematic.PNG](https://www.edaboard.com/data/attachments/53/53344-c442b1a5010062f08ddefebd34f83ebd.jpg)
The original dimensions:
W14=55um ; L14=0.55um
W11=27um ; L11=0.55um
New dimensions (dividing M14 in 4 transistors & M11 in 2 transistors) for each divided transistor:
W14'=W14/4=55um/4=13.75um ; L14'=L14=0.55um;
W11'=W11/2=27um/2=13.5um; L11'=L11=0.55um;
On the following figure you can check them on the layout:
![m14_m11.PNG m14_m11.PNG](https://www.edaboard.com/data/attachments/53/53345-12a256d560496242a1e4236d9f88276e.jpg)
What would be the best combination for the common centroid (with 6 transistors total)? Is there a problem with the dimensions (13.5um vs. 13.75um) between the pair? Should dummies be used?
Thank you very much in advance!