At a first thought, blocking of the light to a photoresistor should trigger an oscillator at full volume, just removing some of the light, should trigger the same oscillator at a reduced volume.
So you need a trigger circuit that switches on the oscillator at a reduction of, say, 1% of the light. Then you need some circuit that alters the level of the oscillator by the DC corresponding to the light level.
So the first thing, are your lasers too powerful, the output from the photoresistors must drop when the light beam is reduced by 1%. Which makes me think, that the laser should have its optics arranges so the light beam is 10mm in diameter, trying to intercept a beam that is only 2mm will be too difficult. I think for simplicity I would go for a central light source (50 watt DC bulb), feeding optic fibres into each individual lens.
So you need a 12V DC supply. Feed the photoresistor fro +12V, connect a resistor to earth from this junction. Repeat the same arrangement but with a variable resistor in place of the photoresistor. The two junctions go to a comparators inputs. With adjustment of the variable resistor you should then get the output of the comparator to swing from 0V to 12V, which you use as the feed to the oscillator. Now you have to take a sniff of the voltage across the photoresistor and amplify it so the change of voltage form full light to zero light becomes a worthwhile amount , say 0 -> 5V and use this to vary the gain of an amplifier to so feeding the oscillator through it, the level of the note changes in proportion to the amount of light blocked.
Without any data on the photoresistor and its change of resistance due to the light it is not possible to say more.
Frank