Laplace transform of integral

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E-design

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I was working on a project and saw the following in the calculations:

Laplace[∫ E(t) dt] = E/s^2

Is this correct? Shouldn't it be E/s?
 

E-design said:
I was working on a project and saw the following in the calculations:

Laplace[∫ E(t) dt] = E/s^2

Is this correct? Shouldn't it be E/s?
Click to expand...

It should be

Laplace[∫ e(u) du] = E(s)/s

provided that the limits of the integral are 0 and t. (I put u as the integration variable in order to avoid confusions.)

regards

Z
 
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