Continue to Site

Welcome to EDAboard.com

Welcome to our site! EDAboard.com is an international Electronics Discussion Forum focused on EDA software, circuits, schematics, books, theory, papers, asic, pld, 8051, DSP, Network, RF, Analog Design, PCB, Service Manuals... and a whole lot more! To participate you need to register. Registration is free. Click here to register now.

Laplace Transform for x(t)=0?

Status
Not open for further replies.

alishel

Newbie level 3
Newbie level 3
Joined
May 9, 2006
Messages
3
Helped
0
Reputation
0
Reaction score
0
Trophy points
1,281
Activity points
1,296
Hi guys i have one question. i am just wondering what's the Laplace Transform for x(t)=0? is it 0 as well? my homework is due tomorrow :(

thanks in advance :)
 

f(s)=integral ( x(t) e^-st)dt limits 0 to inf

x(t)=0

lets look, are there (0 x inf) ?

f(s)=0*integral (e^-st)dt

f(s)=0*(-1/s)(e^-st) limits 0 to inf

f(s)=0
 

    alishel

    Points: 2
    Helpful Answer Positive Rating
THe Laplace transform of e^(-at) is 1/s+a so 1 = e(-0t), so its transform is 1/s.

Added after 2 minutes:

so for 0, we got e^(-infinity*t), so for 0 it is 0.
 

    alishel

    Points: 2
    Helpful Answer Positive Rating
Thank you both of you. very well-explained :)
 

Status
Not open for further replies.

Part and Inventory Search

Welcome to EDABoard.com

Sponsor

Back
Top