Hi Brad,
Thank you for taking to time to reply to me. I am using the thermistor as a point of reference as what I have gathered so far is that the thermopile is used to calculate the difference (not the actual) between the cold and hot junctions and provides this value as a voltage at the output.
The thermistor itself is not linear and needs a variation of Stein-Harts equation to calculate the correct value given the current resistence (see
here) which is completed in software. The thermopile will be used to read the temperatures of various objects placed in its FOV.
For the conversion from voltage to temp, I have found an
article with explains the basics for calculating the voltage for a T- Type thermocouple which I'm not sure is correct but it gets me close to the value I want.
I've been playing about with the gain experimentally over the last few days and honed it into a value between 1000-2000. Haven't decided on a crisp number yet but i've tabled the values of resistance for this and will be choosing a whole number for ease of calculations later. And yes, very unwieldly! By addon voltage I am assumming you mean the voltage supplied (via 10k/1k divider network) to the negative input of the Op-Amp to pose as a virtual ground and thereby compensate for some of the noise of the system. This currently sits at 0.447 volts given a Vs of slightly less than 5V.
When measuring a sample temperature:
-I first measure the Vout of the Thermopile when no object is present in its FOV
-Place an object infront of the thermopile and give it a minute
-Subtract current Vout from previous Vout to provide the difference
-Subtract Vref (0.447V)
-Divide by the gain and scale to micro Volts
-I then use this value in the calculation provided by the earlier link having already pre-calculated the other variables needed.
Hope this makes sense. Going to be looking closer at the algorithm today and try not to pull my hair out!
Regards,
P-J-V